Cities and letter values (Preview)

Apologies for my absence, Puzzlers! I'm currently wrapping up a huge personal project, but I'll try to keep up with this puzzle blog going forward.

This week's puzzle is a pretty straightforward solve, fortunately. Let's take a look:

This week's challenge comes from listener Al Gori, of Oak Ridge, N.J. Name a famous city in 10 letters that contains an "S." Drop the "S." Then assign the remaining nine letters their standard value in the alphabet — A = 1, B= 2, C = 3, etc. The total value of the nine letters is only 25. What city is it?

 To solve this puzzle, we need:

• C: a list of cities;
• I'm planning to use this one; it looks pretty good, and it's downloadable as a CSV, so we can easily pull the names from that without needing to scrape and clean HTML.
• We'll filter this so that we keep only city names that contain 10 letters (not counting spaces, hyphens, etc.) and exactly one 's'.
• function_lvs: Letter value sum function to take a string (a city name), look up the numerical value in the alphabet for each letter (minus the 's') and return that sum;
• for c in C: 
• if function_lvs(c) == 25:
• print("Solution! "+c)

Come back here after NPR's Thursday deadline to see my solution and implementation. Good luck!